8s^2+36s+4=0

Solution for 8s^2+36s+4=0 equation:

8s^2+36s+4=0

a = 8; b = 36; c = +4;
Δ = b2-4ac
Δ = 362-4·8·4
Δ = 1168
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1168}=\sqrt{16*73}=\sqrt{16}*\sqrt{73}=4\sqrt{73}$
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-4\sqrt{73}}{2*8}=\frac{-36-4\sqrt{73}}{16}
$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+4\sqrt{73}}{2*8}=\frac{-36+4\sqrt{73}}{16}
$